# Urgent: de Brogile wavelengths of atoms, working in eV!

Lavace

## Homework Statement

http://www.strings.ph.qmul.ac.uk/~russo/QP/r06QPHYEX.pdf [Broken]
Question 3.

## The Attempt at a Solution

I can easily derive the equation I need, which is:

lamda = h/p

Which after some playing around with K.E =1/2mv^2 etc we obtain:

lambda (de brogile) = h/SQRT(2mKE)

Here is the data we are provided with in the exam (see sheet 1): http://www.strings.ph.qmul.ac.uk/~russo/QP/week6.pdf [Broken]

Everythings in eV and MeV, I plug in the values constantly, tried converting h to joules, and the electron mass to kg etc, but no avail as I don't think I know what Im doing with it, and I can't seem to obtain the real answer which is: 1.2 x10^-9m

Anyone explain how to do this quickly? I understand the theory behind this top notch but missed on how to use eV etc.

THANKS.

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Gold Member
The equation appears to be right (I plugged in values and got the right answer), what kind of answers are you getting? It's probably just an arithmetic error, or a unit error.

Lavace

I plugged in:
4.14x10^-21 / SQRT(2 x 0.511 x 1.6x10-24) = 3.2 x 10-9.

I converted 1eV into MeV. Where am I going wrong with this?
If I convert everything to eV and use:
4.14x10^-15 / SQRT(2 x 511 x 1.6x10-19) = 3.2 x 10-7m

Still wrong, and I'm ripping my hair out on this!

Gold Member
Well, when you use electron volts, what speed comes out? It's not meters/second, but rather c.

Also, you have some wrong values. The electron is 511keV = .511MeV (correct for your calculation in MeV) = 511000eV (incorrect when you plugged it in eV).

Also, you're converting 1 eV into joules which doesn't make sense since you used everything else in eV.

Lavace
So how would I go about doing this?

Would I multiply the value of the rest mass by (3x10^8)^2 to obtain the MeV value?