Urgent - fiber optics illumination system

  • Thread starter Aleksee
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  • #1
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Hello everyone,
Am having a research about the use of fiber optics in illuminating a room for example by taking solar power.
What are the formulas that are used in order to know how much length do we need and how many fibers we need in order to have for example the power of a 60 watt lamp?

I appreciate it.
Thank you.
 

Answers and Replies

  • #2
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Fibers can transport quite a bit of power, the losses depend on the bends. You will need some collimating optics. Why don't you approximate the necessary sizes by the size of a window that you would put into the same room. I am sure there are good books about this.
 
  • #3
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As far as delivering/accepting the light:

The amount of light a fiber can collect is based on it's Numerical Aperture (NA). The math for this is based on a index of refraction of the core and a cladding that the fiber is made of. Basically the NA tells you which light will enter and stay in your fiber as a function of angle.

For transporting a large amount of light for illumination plastic optical fiber will work well enough and be much easier to work with. They are based on the same principles but much more durable, easier to work with, and cheaper.


http://en.wikipedia.org/wiki/Numerical_aperture#Fiber_optics
http://en.wikipedia.org/wiki/Plastic_optical_fiber
http://www.pofeska.com/pofeskae/tece/whatspofe/whatspofe.htm [Broken]

Then knowing the intensity of light from the sun in your area and the angle at which the fiber will be placed in relation to the sun you can figure out how much light to expect. This will of course vary throughout the day as the light from the sun has to go through more atmosphere and the angle of incidence to your fiber/window changes.
 
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