- #1

kangta

2. Does the force of kinetic friction depend on the weight of the object? Explain.

3. Does the coefficient of kinetic friction depend on the weight of the object? explain

This is not on an icline plane.

- Thread starter kangta
- Start date

- #1

kangta

2. Does the force of kinetic friction depend on the weight of the object? Explain.

3. Does the coefficient of kinetic friction depend on the weight of the object? explain

This is not on an icline plane.

- #2

- 43

- 0

F = μR

μ does not = 0

where F = friction, R = normal reaction force and μ = coefficient of friction.

if F = 0, then R must also equal 0 to satisfy the above equation. therfore a graph of F against R would pass through the origin.

2. yes.

for an object moving on a horizontal plane, R = mg (where mg = weight). therefore, for an object moving on a horizontal plane:

F = μmg

3. no.

F is proportional to R and hence F is proportional to mg. μ is just the constant of proportionality. it is a property of the surface(s) experiencing friction. it is dependant upon the shape and material of the surfaces.

- #3

kangta

ummm i don;t get what those things mean...

what is R?

Can you explain it in a simpler way?

what is R?

Can you explain it in a simpler way?

- #4

kangta

The equations given to me are

ì = Ff/Fn

Fnet = mg

ì = Ff/Fn

Fnet = mg

- #5

- 43

- 0

in the equation i used, F is the frictional force acting on an object moving on a surface, R is the normal reaction force on the object and μ is the coefficient of friction between the object and the surface.

the frictional force F on the object is proportional to the normal reaction force R acting on the object:

F is proportional to R.

to turn this into an equation, a constant of proportionality is required. this is μ, the coefficient of friction:

F = μR

μ cannot = 0. if μ = 0 there would be no friction.

in a graph of F = μR, F would be the vertical axis and R would be the horizontal axis. μ would be the gradient of the graph. if the graph passes through the origin, then F must = 0 when R = 0. put R = 0 into the equation:

F = μ0

F = 0

so F does = 0 when R = 0 therfore the graph passes through the origin.

- #6

kangta

oop i meant u = Ff/Fn u = coefficent of friction, Fn = Force Normal, Ff = Force of friction.

- #7

kangta

How does the surface area of the block affect the force of friction or the coefficient of friction?

- #8

- 28

- 0

- #9

- 43

- 0

you have used Ff for frictional force, and i have used F. you used Fn for normal reaction force, i used R. you used u for coefficient of friction, i used μ.

u = Ff/Fn can be rearanged to Ff = uFn, which is in the same form as i used.

the area in of the block in contact with the surface it is moving on affects the coefficient of friction u. u is a function of the area of the block in contact with the surface, and the material of the block.

- #10

russ_watters

Mentor

- 19,861

- 6,286

Coeficient of friction includes surface area and surface area relates pressure and force. So if you increase surface area, the pressure decreases (for a given force) and the 'amount of surface to grab' increases by the same amount. So the friction force stays the same.Originally posted by kangta

How does the surface area of the block affect the force of friction or the coefficient of friction?

I'm not sure if that made sense, so let me try a mathematical explanation: if you break out a surface area term from the coefficient of friction, you also have to divide force by surface area (getting pressure). The two surface area terms cancel out.

- #11

- 43

- 0

this has nothing to do with pressure.

the coefficient of friction μ is a function of the contact area between the two surfaces amongst other things.

F = μR

μ = f(A) where f(A) is a function of the contact area. thus by changing A you change μ. by changing μ you change the frictional force for a given normal reaction force.

you can test this by experiment. two objects of identical mass but with different contact areas moving on a horizontal plane will experience different frictional forces.

this is why, for example, wide tyres give more grip than narrow tyres.

the coefficient of friction μ is a function of the contact area between the two surfaces amongst other things.

F = μR

μ = f(A) where f(A) is a function of the contact area. thus by changing A you change μ. by changing μ you change the frictional force for a given normal reaction force.

you can test this by experiment. two objects of identical mass but with different contact areas moving on a horizontal plane will experience different frictional forces.

this is why, for example, wide tyres give more grip than narrow tyres.

Last edited:

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 4

- Views
- 3K

- Last Post

- Replies
- 1

- Views
- 3K

- Last Post

- Replies
- 3

- Views
- 1K

- Replies
- 5

- Views
- 2K

- Last Post

- Replies
- 14

- Views
- 3K

- Replies
- 1

- Views
- 2K

- Replies
- 1

- Views
- 1K

- Last Post

- Replies
- 11

- Views
- 2K