I need to solve for the equivalent resistance of the circuit below:https://s.yimg.com/hd/answers/i/7936cef74d9a45cfb7c9f051c19041dd_A.jpeg?a=answers&mr=0&x=1427780127&s=19cab3f26be71f84b6bb2d7d291a5217 [Broken] Voltage is 100volts. R1=6ohm, R2=8 ohm, R3= 4 ohm, R4=8 ohm, R5= 4 ohm,R6= 6ohm, R7=ohm R8=10 ohm, R9=6 ohm, R10= 2 ohm. Thanks :) 2. Relevant equations V=IR V=IP P=I^2R SERIES: VTOT=V1+V2 ITOT=I1=I2 RTOT=R1+R2 PARALLEL: VTOT=V1=V2 ITOT=I1+I2 REQ=(1/R+1/R2)^-1 3. The attempt at a solution I believe R1 and R2 are in a series. So adding them up would mean R1+2=14ohm We know the voltage is 100volts so I did 100/14=I I=7.14 amps then I believe we could find the voltage of R1 and R2. Voltage of R1= 6x7.14=42.85V Voltage of R2=8x7.14=57.12V Knowing that VTOT=V1+V2, 57.12+42.85=pretty close to 100V. Then the triangle circuits just make me go what... I believe they're in a series? Not sure.