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**Urgent help needed, please!!!! Circular motion**

Suppose the surface (radius = r) of the space station is rotating at 42.7 m/s. What must be the value of r for the astronauts to weigh one-half of their earth weight?

My soln: Let // represent square root

V = // (GMe/r)

I divided Me by 2 and made r the subject

r = GMe/V^2

but i got the anser wrong