Suppose the skin temperature of a naked person is 34°C when the person is standing inside a room whose temperature is 25°C. The skin area of the individual is 2.0 m2(adsbygoogle = window.adsbygoogle || []).push({});

a) Assuming the emissivity is 0.80, find the net loss of radiant power from the body

b) Determine the number of food Calories of energy (1 food Calorie = 4186 J) that is lost in one hour due to the net loss rate obtained in part (a). Metabolic conversion of food into energy replaces this loss.

I used

a)

Q/t = emissivity x stefan-boltzmann constant x T^4 x A

= 0.8 X 5.67^-8 X 298.15^4 X 2

=719.277

b) 1 watt per hour = 3600J

total joules = 3600 X 719.277 = 2589399.087

2589399.087 /4186 = total calories

Answers are wrong

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# Urgent help needed please. Radiation question

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