Urgent help needed with finding angular speed??? This is impossible!! I've even asked on Y!A and THEY all got it WRONG. Webassign says the answer is 32.9 but how??? This is so freaking frustrating..........anlfdsfjlkdjf Ok...so what I tried doing was ask myself what the equation for angular speed was. ω = at And then I realized, they don't give me time. So I MUST use some OTHER equation to find angular speed. And then I realized that the key word in the problem was that sphere STARTED FROM REST (INITIAL POSITION) and ENDED AT THE BOTTOM OF THE SLOPE (FINAL.) And then I was like OHHHHH.... ok this should be a freaking walk in the park... -.- PEinitial + [STRIKE]KEinitial[/STRIKE] = [STRIKE]PEfinal[/STRIKE] + KEfinal In other words, the ball has PE at the top when it's at rest and no KE, and when it rolls to the bottom it has no PE but it has KE. So... 1) PEinitial = KEfinal mgh = (1/2)mω2 2) Find mass and plug it in equation above F = ma (300 N) = m(9.8) 300/9.8 = m 30.61 kg = m And then here I said to myself "for the love of God...mass cancels out anyways -.- what a huge waste of time" 3) gh = (1/2)ω2 (9.8)(6 sin 31) = (0.5)ω2 30.28 = (0.5)ω2 30.28/0.5 = ω2 60.56 = ω2 7.78 = ω ?????? Help? Can someone please SHOW me and explain to me how they got 32.9?