- #1

An electron is trapped in an infinite quantum well. If the lowest energy transition is to produce a photon of 450nm-wavelength, what should be the well's width?

Any help is appreciated. :)

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- Thread starter SuperCheetah
- Start date

- #1

An electron is trapped in an infinite quantum well. If the lowest energy transition is to produce a photon of 450nm-wavelength, what should be the well's width?

Any help is appreciated. :)

- #2

The energy eigenvalue equation for an electron in a 1-D infinite square well is:

E(n) = (h^2 * n^2) / (8 * m * L^2),

where*L* is the width of the well.

A transition of energy states requires an emission or an absorption of a photon. The energy of a photon is:

E = h * f,

where*f* is the frequency of the photon.

Now you've got the equations; all you have to do is plug and chug.

eNtRopY

E(n) = (h^2 * n^2) / (8 * m * L^2),

where

A transition of energy states requires an emission or an absorption of a photon. The energy of a photon is:

E = h * f,

where

Now you've got the equations; all you have to do is plug and chug.

eNtRopY

Last edited by a moderator:

- #3

Nevermind got the frequency, my books equation says that there is a 2 on the bottom instead of an 8?

Last edited by a moderator:

- #4

- #5

I´m not sure what you are doing with the equation, but you are looking for a difference, a delta E, dose that help?

Could you check you answer again, I´m getting an answer of ~ 6.4*10^(-10)???

- #6

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