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Urgent question: G-Force, Deceleration, loads

  • Thread starter exalto1
  • Start date
  • #1
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Hello...

If an object weighs 4500kg and travels @ 5kph (138cm/s) then stops in 15cm:

what is Gforce?

Decceleration?

Also, if object was stopped via a collision and if contact face is 100cmx15cm then what is impact force kg/sq.cm?

This information is really important to me for a professional argument that may save my job so ANY help/resources would be immensely appreciated.

Yes I did have an accident at work... :redface:

My only defence is going to have to be with cold science.

At 36, my algebra has rusted through as this is the first time i've had to find "x" so really need some whizzy help.

Thanks to anyone kind enough to help.

David
 
Last edited:

Answers and Replies

  • #2
4
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If something travels with the initial velocity V.......
1.38m/s

and then stops over the distance L,.....................
0.15m

then, assuming constant decelleration,

L = V^2/2a...........................................

0.15m=1.38m^2/2 x 6.348
0.15=1.9044/12.696


where V - initial velocity
a - absolute value of decceleration.
V^2 means "V squared"

From this, you can find

a = V^2/2L................................................ ......

a=1.38m^2/0.30m
a=6.348m/s

From the Newton's law,

a = F/M................................................. ...

6.348m/s=28566n/4500kg

where F is the force that acted during the slowdown and M is the mass.

We then have

F = MV^2/2L.............................

4500kg x 1.38m/s^2 /2 x 0.15m
4500 x 1.9044 / 0.30m
8569.8/0.30
F=28566n

Use M in kilograms, V in meters per second and L in meters. You'll get the force in Newtons.

I don't know what is Gforce.

Then the pressure is by definition the force divided by area. Diveide the force you've obtained by the area and you'll get pressure in Newtons per unit of area (whatever units you use).....

28566n/1.5m=19044n/sq m
or 1941.9kg/sq m

If someone could check this please I'd be grateful as i'm a little woozy with painkillers.

Thank you so very much.
 
  • #3
alphysicist
Homework Helper
2,238
1
Hi exalto1,

Then the pressure is by definition the force divided by area. Diveide the force you've obtained by the area and you'll get pressure in Newtons per unit of area (whatever units you use).....[/B]
28566n/1.5m=19044n/sq m
or 1941.9kg/sq m
I'm not sure about these numbers. The area in square meters is .15 m^2.

G-force is usually the acceleration measured in units of g=9.8 m/s^2.
 
  • #4
4
0
Hello alphysicist...

Are these figures better:


P = 28566N/1500cm^2=19.044N/cm^2 or
P =~1.94kg/cm^2 or
P=~19400kg/m^2
 
  • #5
alphysicist
Homework Helper
2,238
1
Hello alphysicist...

Are these figures better:


P = 28566N/1500cm^2=19.044N/cm^2 or
P =~1.94kg/cm^2 or
P=~19400kg/m^2
Your math look okay to me, if those are the units you want. Using kg/cm^2 for the pressure reminded me that a unit that some people use for force is the gram-force. I would think that's probably what they meant by Gforce, so your choice of mass/area as the units for pressure would be what they wanted.
 
  • #6
4
0
Thank you so very much Al
 

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