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Urgent - Resistive Bridge

  1. Nov 21, 2008 #1
    1. The problem statement, all variables and given/known data
    I was trying to apply the formula of bridge


    2. Relevant equations
    [tex]V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})[/tex]


    3. The attempt at a solution
    File is attached....Small numbers with resistor names are their values in ohms...
    the answer I get is 6v....Here it is 1.5 v....
     

    Attached Files:

    Last edited by a moderator: Nov 21, 2008
  2. jcsd
  3. Nov 22, 2008 #2

    CEL

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    The equation should be:
    [tex]V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s[/tex]
    With[tex]V_s = 3V[/tex] you could never have [tex]V_o = 6V[/tex] with a totally passive circuit.
     
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