# Urgent - Resistive Bridge

## Homework Statement

I was trying to apply the formula of bridge

## Homework Equations

$$V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})$$

## The Attempt at a Solution

File is attached....Small numbers with resistor names are their values in ohms...
the answer I get is 6v....Here it is 1.5 v....

#### Attachments

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## Homework Statement

I was trying to apply the formula of bridge

## Homework Equations

$$V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})$$

## The Attempt at a Solution

File is attached....Small numbers with resistor names are their values in ohms...
the answer I get is 6v....Here it is 1.5 v....

The equation should be:
$$V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s$$
With$$V_s = 3V$$ you could never have $$V_o = 6V$$ with a totally passive circuit.