# Homework Help: Urgent - Resistive Bridge

1. Nov 21, 2008

### Altairs

1. The problem statement, all variables and given/known data
I was trying to apply the formula of bridge

2. Relevant equations
$$V_{o} = (\frac{1}{1+R4/R2})-(\frac{1}{1+R3/R1})$$

3. The attempt at a solution
File is attached....Small numbers with resistor names are their values in ohms...
the answer I get is 6v....Here it is 1.5 v....

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Last edited by a moderator: Nov 21, 2008
2. Nov 22, 2008

### CEL

The equation should be:
$$V_{o} = [(\frac{1}{1+R4/R3})-(\frac{1}{1+R2/R1})]V_s$$
With$$V_s = 3V$$ you could never have $$V_o = 6V$$ with a totally passive circuit.