1. The problem statement, all variables and given/known data Solve for x. x is greater than or equal to 0 and x is less than or equal to 2pi. (4/3)sinxcosx-sin22x=0 If there is a better way to approach this question than the way I did it below, please post it. Thanks. 2. Relevant equations N/A 3. The attempt at a solution (4/3)sinxcosx-sin22x=0 2(2sinxcosx)-3sin22x=0 2(sin2x)-3sin22x=0 2sin2x-3sin22x=0 sin2x(2-3sinx)=0 <------I know this is incorrect. How do I factor the previous line correctly? To solve the first part: sin2x=0 2x=sin-1(0)=0,pi,2pi,3pi,4pi therefore x=0, pi/2, pi, 3pi/2, 2pi I know there are other solutions for x. Please help!