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Urgent Tangential Speed Question

  1. Mar 1, 2010 #1
    1. The problem statement, all variables and given/known data

    If the rotation of a planet of radius 5.99x10^6 m and free-fall acceleration 7.87 m/s^2 increased to the point that the centripetal acceleration was equal to the gravitational acceleration at the equator, what would be the tangential speed of a person standing at the equator?

    2. Relevant equations
    Vt=rW (tangential velocity equals radius times omega, or angular velocity)

    3. The attempt at a solution
    I don't even know how to go about solving this. The way the problem is set up is confusing to me. This is the only problem out 30 some-odd questions that I have not done correctly. My homework is due at 12:00 tonight and I have almost an A, but this question is really bothering me. Can someone help?
  2. jcsd
  3. Mar 1, 2010 #2


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    I hope you're not on Eastern Standard Time. You are given the gravitational acceleration. What's the formula for centripetal acceleration? Set them equal.. you'll be going real fast....
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