- #1

- 276

- 0

of

1 over x*sqrt(t^(2) - 1) dx

I noticed that this was just the arcsece, so I got arcsec(x) for the answer, but how would I evaluated this at 2 and sqrt(2)?????

What did i do wrong?

Thank you!

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- Thread starter frasifrasi
- Start date

- #1

- 276

- 0

of

1 over x*sqrt(t^(2) - 1) dx

I noticed that this was just the arcsece, so I got arcsec(x) for the answer, but how would I evaluated this at 2 and sqrt(2)?????

What did i do wrong?

Thank you!

- #2

Defennder

Homework Helper

- 2,591

- 5

- #3

- 1,753

- 1

more clarity and a little more work would be appreciated

- #4

- 276

- 0

1 over x*sqrt(x^(2) - 1) dx

--> which I evaluated to be arcsec (x),but this doesn't make sense with the limits of integration...

- #5

rock.freak667

Homework Helper

- 6,223

- 31

Let [itex]\alpha=sec^{-1}(\sqrt{2})[/itex]

so that [itex]sec\alpha=\sqrt{2}[/itex]

and therefore [itex]cos\alpha=\frac{1}{\sqrt{2}}[/itex] and then you find [itex]\alpha[/itex]

OR...somewhere in you attempt you would have used the substitution x=sec[itex]\theta[/itex] so from there you could have gotten [itex]\theta=cos^{-1}(\frac{1}{x})[/itex] and use that instead of arcsec

- #6

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Oh my god!

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