ello ello! Here is the problem: Let g(t) be the solution of the initial value problem: http://cwcsrv11.cwc.psu.edu/webwork2_files/tmp/equations/da/9fc0e62bc2df5df4721f38c5634c1f1.png [Broken] with g(1) = 1 . Find g(t). g(t) = ? Heres what i did: 2ty' + y = 0; y' + y/(2t) = 0; I(t) = e^(2t) dt integrate: I = t^2; t^2*y = C; y = C/t^2; apply intial condition: g(1) = 1; 1 = C/1 C = 1; Appply constant: y = 1/t^2; which si wrong! :surprised Anyone know what I did?