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Here is the problem:

Let g(t) be the solution of the initial value problem:

http://cwcsrv11.cwc.psu.edu/webwork2_files/tmp/equations/da/9fc0e62bc2df5df4721f38c5634c1f1.png [Broken]

with g(1) = 1 .

Find g(t).

g(t) = ?

Heres what i did:

2ty' + y = 0;

y' + y/(2t) = 0;

I(t) = e^(2t) dt

integrate:

I = t^2;

t^2*y = C;

y = C/t^2;

apply intial condition: g(1) = 1;

1 = C/1

C = 1;

Appply constant:

y = 1/t^2;

which si wrong! :surprised

Anyone know what I did?

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# Urnt? easy integration factor D.E. but its != correct, ahh!

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