- #1
scorpa
- 361
- 1
Hello everyone,
Unfortunately, my calculus class has just gotten to my least favorite subject in the world...limits. There are a few questions I am hopelessly stuck on. Any help would be appreciated.
The limit as x approaches 1 of (square root x -x^2)/(1-square root x)
I have no idea how to go about this one. I know that usually when you have a square root you rationalize the equation, but when you have one in the denominator and numerator what do you do?
Use the Intermediate Value Theorem toshow that there is a root of the given equation in the specified interval. Tanx=2x, (0,1.4)
For this one I changed it into the form f(x)=tanx-2x , then I found that f(0)=0 and f(1.4)=2.99 therefore f(0) < 0 < f(2). Is this all I have to do, Is this enough to satisfy the question asking if there is a root between (0,1.4)?
My next questions are ones I was able to get answers for but am unsure of whether I did them correctly.
Find the limit as x->2 of (2x^2+1)/(x^2+6x-4).
For this one I believe you are able to simply substitute 2 in for x and that will give you an answer of 3/4
Find the lim as x ->1 of (x^3-1)/(x^2-1)
For this question I factored out (x-1) and from there I was able to get an answer of (3/2).
My other questions are similar, and if I know I did these right I can be fairly sure the others are correct. Thank you so much for your time and help.
Unfortunately, my calculus class has just gotten to my least favorite subject in the world...limits. There are a few questions I am hopelessly stuck on. Any help would be appreciated.
The limit as x approaches 1 of (square root x -x^2)/(1-square root x)
I have no idea how to go about this one. I know that usually when you have a square root you rationalize the equation, but when you have one in the denominator and numerator what do you do?
Use the Intermediate Value Theorem toshow that there is a root of the given equation in the specified interval. Tanx=2x, (0,1.4)
For this one I changed it into the form f(x)=tanx-2x , then I found that f(0)=0 and f(1.4)=2.99 therefore f(0) < 0 < f(2). Is this all I have to do, Is this enough to satisfy the question asking if there is a root between (0,1.4)?
My next questions are ones I was able to get answers for but am unsure of whether I did them correctly.
Find the limit as x->2 of (2x^2+1)/(x^2+6x-4).
For this one I believe you are able to simply substitute 2 in for x and that will give you an answer of 3/4
Find the lim as x ->1 of (x^3-1)/(x^2-1)
For this question I factored out (x-1) and from there I was able to get an answer of (3/2).
My other questions are similar, and if I know I did these right I can be fairly sure the others are correct. Thank you so much for your time and help.