Someone plz show me how to do the problem below, thanks very much.

1)***Use the known area of a circle to find the value of the integral

integral from -a to a of the function sqrt(a^2-x^2)dx.

2)***Then use the result of this integral to find the enclosed area of (x^2)/(a^2)+(y^2)/(b^2)= 1, a>b>0.

Plz show me how to integrate #1

1)***Use the known area of a circle to find the value of the integral

integral from -a to a of the function sqrt(a^2-x^2)dx.

2)***Then use the result of this integral to find the enclosed area of (x^2)/(a^2)+(y^2)/(b^2)= 1, a>b>0.

Plz show me how to integrate #1

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