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Using Area to Find Dimensions

  1. Mar 5, 2008 #1
    Hey I have two questions that I do not know how to answer...help? Please try to answer at a grade 10 level! And, this isn't a homework question.

    1. A yard is to be enclosed by 40 meters of fencing. If all of the fencing is used, what dimensions will result in a yard with an area of 75m^2?

    2. What is the maximum area of a right angle triangle whose hypotenuse is 10 cm and perimeter is 26 cm?
     
    Last edited: Mar 5, 2008
  2. jcsd
  3. Mar 5, 2008 #2

    symbolipoint

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    #1:
    You are saying that the perimeter is 40 meters. You should be able to develop this information:
    [tex] \[
    \begin{array}{l}
    p = perimeter \\
    75 = theArea \\
    p = 2x + 2y \\
    75 = xy \\
    \end{array}
    \]
    [/tex]
     
  4. Mar 5, 2008 #3

    symbolipoint

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    Please note that in the above, I assumed that the yard is rectangular shaped.
     
  5. Mar 6, 2008 #4
    Exactly, and if you use that method for #1, you end up with two equations and two variables which is easily solved.

    For #2:
    So you know that c^2=a^2+b^2
    You also know that p=a+b+c
    c and p are known variables, and b and a are your unknowns. Therefore, you once again have two equations and two unknowns: solvable.
     
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