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In the diagram given, the pulley is frictionless and the force of friction between the .5kg mass and the table is 4.8 N. The force equation for the spring is F = 50x. If the system starts at rest with the spring at its normal length, calculate the maximum speed the 1kg mass will reach.
P.S. I have the answer, I just don't know how to get there.
Okay, so here are the equations I have during this unit:
Force of the Spring= kx (k is 50 in this question)
Kinetic Energy = 1/2 mv^2
Potential Energy = mgh
Potential Energy of the spring = 1/2kx^2
Total Energy = sum of all energy
Then from a previous unit, this equation might be needed:
Fnet = Fgravity -T where T is the tension in the string
The Attempt at a Solution
KE = 1/2 mv^2
KE = 0.5kg (0m/s)^
KE = 0Joules
PE(spring) = 1/2 kx^2
PE(spring) = 1/2 (50) 0m^2
PE(spring) = 0 Joules
PE = mgh
PE = 1kg(9.8 N/kg)(0m)
PE = 0
Fnet = Fg + T
1kg(a(1kg object)) = 9.8N/kg (1kg) -T T
A(1kg object) = (9.8N -T)/1kg
Fnet = Fg + T
0.5kg (a(0.5 kg object)) = 0N/kg (0.5kg) -T
a(0.5kg object) = -T/ 0.5kg
I don't know what to do from here, or what I did wrong. I missed a couple of days at school, so I'll admit that I'm a little bit lost.
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