a,b,c,d,e,f belong to Real numbers
Prove that d, e, f can be expressed as linear combinations of a, b and c in such way:
e = (c1+c6)*a+(c2+c4)*b+(c3+c5)*c
c1, c2, c3, c4, c5, c5 >=0
The Attempt at a Solution
Only thing I can prove is that c1+c2+c3+c4+c5+c6 = 1 (using a+b+c=d+e+f).
I think I need to find some expression for b, to be able do something, but I'm not sure.