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## Homework Statement

∫[itex]\frac{1}{x^{2}*ln(x)}[/itex]

## Homework Equations

∫udv = uv-∫vdu

u=ln(x)

du = [itex]\frac{1}{x}[/itex]dx

dv = [itex]x^{2}[/itex]dx

v = [itex]\frac{x^{3}}{3}[/itex]

## The Attempt at a Solution

Using the above formula I got [itex]\frac{x^{3}}{3}[/itex]*ln(x) - [itex]\frac{x^{3}}{9}[/itex] + C

Am I doing this correctly or do I have to input u= [itex]\frac{1}{ln(x)}[/itex] and dv = [itex]\frac{1}{x^{2}}[/itex]