I wish to find the value of .8^(2/5) using logs. I can find the value of .8^(-2/5) as follows: =(log(8)X1/10)X-2/5(adsbygoogle = window.adsbygoogle || []).push({});

=(-1 + .9031)X-2/5 = (-.0969)X-2/5 = +.03876;

antilog(.03876) = 1.093;

Now to find .8^(2/5) my approach is the same:

log(.8)X2/5 = (log(8)X10^-1)X2/5

= (bar1 + .9031)X2/5 : what do I do next. (bar1 = -1)

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# Homework Help: Using logs in calculations

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