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Using Logs to solve for x

  1. Jun 7, 2012 #1
    1. The problem statement, all variables and given/known data

    Solve:

    log6(2x-5)+1=log6(7x+10)

    2. Relevant equations

    -None-

    3. The attempt at a solution

    I know we will need to exponentiate both side by 6 to get rid of the log, or either take another log.

    I need help with getting rid of the +1 on the left side of the = sign because that is what is baffling me.
     
  2. jcsd
  3. Jun 7, 2012 #2
    Hint: [itex]6^{1+a} = 6 \times 6^a[/itex], doesn't it?
     
  4. Jun 7, 2012 #3
    log6(2x-5)+1=log6(7x+10)

    6log6(2x-5)+1=6log6(7x+10)

    6(2x-5)=7x+10

    12x-30=7x+10

    5x=40

    x=8

    I checked it and it worked, thanks for the help man!
     
  5. Jun 7, 2012 #4
    log66 = ?

    Chet
     
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