# Using Logs to solve for x

1. Jun 7, 2012

### darshanpatel

1. The problem statement, all variables and given/known data

Solve:

log6(2x-5)+1=log6(7x+10)

2. Relevant equations

-None-

3. The attempt at a solution

I know we will need to exponentiate both side by 6 to get rid of the log, or either take another log.

I need help with getting rid of the +1 on the left side of the = sign because that is what is baffling me.

2. Jun 7, 2012

### Muphrid

Hint: $6^{1+a} = 6 \times 6^a$, doesn't it?

3. Jun 7, 2012

### darshanpatel

log6(2x-5)+1=log6(7x+10)

6log6(2x-5)+1=6log6(7x+10)

6(2x-5)=7x+10

12x-30=7x+10

5x=40

x=8

I checked it and it worked, thanks for the help man!

4. Jun 7, 2012

log66 = ?

Chet