- #1

jimmyboykun

- 39

- 0

## Homework Statement

Converting the energy of one food calorie into mechanical energy, starting from rest, to what speed could you accelerate a 133-lbs person?

## Homework Equations

1 calorie= 4.184J

1 lbs= 0.453592kg

K=1/2mv^2

## The Attempt at a Solution

here what I did, I converted the lbs to kg which was 60.33kg. I was under the impression to use kinetic energy.

4.184J=1/2(60.33kg)v^2

4.184J/30.165kg=v^2

sqrt 4.184J/30.165kg= 0.372m/s

This is how I solved my problem, but I got 1 out of 10. Can someone explain to me what I did wrong?