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Using nodal find out v1 and v2

  • Thread starter circuitaki
  • Start date
  • #1
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hi dears,

kindly tell me the complete procedre to find out the v1 and v2



v1= -145/8

v2 = 5/2

I have tried it and I reach here

Apply Source transformation theorem.The 5A and 3ohms &2 ohms are converted into single voltage source 25V ( 5A*3+2) in series with 5ohms(3+2).But the positive terminal connected to ground pin.
Similarly 2A and 4ohms are converted into single voltage source 8V( 2A*4ohm) in series with 4 ohm resistor



hhow to go more further I am confuse and am until here am I right or wrong
 

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  • #2
Redbelly98
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Welcome to Physics Forums!

You'll probably get more benefit out of Physics Forums if you become more familiar with the forum rules. Scroll down to the section on Homework Help here:

https://www.physicsforums.com/showthread.php?t=5374

In particular, note that it says:

You MUST show that you have attempted to answer your question in order to receive help. You MUST make use of the homework template, which automatically appears when a new topic is created in the homework help forums.
and
On helping with questions: Any and all assistance given to homework assignments or textbook style exercises should be given only after the questioner has shown some effort in solving the problem. If no attempt is made then the questioner should be asked to provide one before any assistance is given. Under no circumstances should complete solutions be provided to a questioner, whether or not an attempt has been made.
Hope that helps! Show an attempt at solving those homework problems, and then people will be willing to help out.
 
  • #3
The Electrician
Gold Member
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Your subject line says "using nodal". This problem is easy to solve using the nodal method, and you shouldn't do any source transformations.

Do you know what Kirchoff's current law (KCL) is?

What you need to do is write the KCL equations for the two nodes. If you will make an attempt to do that and show your work, then you will get some more help if you need it.
 

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