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Homework Help: Using the formula for a rigid pendulum.

  1. Sep 6, 2012 #1
    How to use the formula for a rigid pendulum?

    Given the formula T = 2π√(2L/3g)
    (1) how do you change to get T^2 = ?
    (2) And then how (1) to get g = ?

    Here's what I've tried, but I'm not sure if they are correct:
    (1) T^2 = 4π^2 x (2L/3g)
    (2) g = [4π^2 x (2L/T^2)] ÷ 3

    (3) The experiment is to find the relationship between length of rod, L and period, T, for a rigid pendulum (i.e rod) hooked onto a stand. When we plot the transformed data onto a graph it should be L vs T^2, but the formula in (2) as I've tried above give 2L/T^2 not L/T^2 as given as the gradient of my graph. So how would I use the gradient to put into the formula (2) to get g (gravity) which should be 9.81ms^-2? Do I double my gradient and substitute that as 2L/T^2?
    Last edited: Sep 6, 2012
  2. jcsd
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