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Calculus and Beyond Homework Help
Utilize the Trapezoid Rule for e^cosx, and find the error
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[QUOTE="leo255, post: 4945030, member: 531078"] [h2]Homework Statement [/h2] Consider the definite integral, from 0 to 4, e^(cosx) dx a) Compute the estimate for this integral using the trapezoid rule with n = 4. b) Find a bound for the error in part a. c) How large should n be to guarantee that the size of the error in using Tn is less than 0.0001 [h2]Homework Equations[/h2] 3. The Attempt at a Solution A)[/B] delta x = b-a/n = 4-0/4 = 1. 1 * [f(0) + 2f(1) + 2f(2) + 2f(3) + f(4)] = [B]To save you time/busy-work, double click the line below, right click, and search via google. It will calculate it for you, and show the exact answer.[/B] e^(cos(0)) + 2 * e^(cos(1)) + 2 * e^(cos(2)) + 2 * e^(cos(3)) + e^(cos(4)) = 2.718 + 3.433 + 1.319 + 0.743 + 0.5220 = 8.733 Problem here: when I calculate this integral with my TI, I get a vastly different number (4.335). Anyway, onto B [B]B)[/B] First derivative: -sin(x) e^(cos(x)) Second derivative: sin^2 (x) e^ (cos(x)) - cos(x) * e^(cos(x)) From here, I'm confused. I don't know exactly how to find "K". I know that it is the absolute value of the largest number possible of the 2nd derivative of the original function (3rd derivative for Simpsons Rule), and that it would be: k(b-a)^3 /12(n)^2. I have read that you may want to make sin/cos functions equal to 1, since that is the highest value they can have, however doing that would yield: 1 * e^1 - 1 * e^1 = e - e = 0 C) Haven't gotten to that point. [/QUOTE]
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Calculus and Beyond Homework Help
Utilize the Trapezoid Rule for e^cosx, and find the error
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