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swayam007
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When Voltage across two points is 0 & current flowing through that connection is 0. Is it a short circuit or open circuit?
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When Voltage across two points is 0 & current flowing through that connection is 0. Is it a short circuit or open circuit?
Ratch said:swayam007,
A short or open is determined by physical contact, not by what voltage is across, current through, or resistance between the contacts. So if the contacts physically touch each other, then you have a short circuit across the contacts.
Ratch
True but, if all you know is that measurements gave you V=0 and I=0, you cannot determine anything about the resistance - infinite / zero / 347Ω.
Ratch said:sophiecentaur,
If you are able to insert an ammeter between the contacts, then you should be able to determine whether they are touching or not, and thereby know whether they are open or closed. The quality of the contacts, such as whether they are dirty or corroded does not mean they are open or shorted. Only a physical inspection can determine that for certain. The resistance of the contacts are a a good indication, but not a certainity of their status.
Ratch
...but unless you have some way of finding current and volts, you can't be sure.
Ratch said:sophiecentaur
Well, assuming a perfect ammeter and voltmeter, the ammeter is going to short out the switch so the voltmeter will always read zero whether the switch is open or closed. So, knowing the current and voltage is no sure way to determine the switch status. For me, physical inspection is the definitive determination.
Ratch
But who, in their right mind, would ever connect an Ammeter in PARALLEL??QUOTE]
I sure wouldn't, but from the OP's description, I envisioned an ammeter in series with the contacts, and a voltmeter across the contacts, both at the same time. That makes the ammeter in parallel with the voltmeter.
Ratch
Ratch said:sophiecentaur,
But who, in their right mind, would ever connect an Ammeter in PARALLEL??QUOTE]
I sure wouldn't, but from the OP's discription, I envisioned an ammeter in series with the contacts, and a voltmeter across the contacts, both at the same time. That makes the ammeter in parallel with the voltmeter.
Ratch
Are you suggesting that the 'original' circuit consisted of just a loop of wire, joining each of the switch contacts together? What sort of a circuit would that be and what possible use could it be?
I was naturally assuming that the contacts were part of an existing circuit and that they happened to have zero volts across them with no current flowing through them (quite a possibility, in fact it could be part of a balanced bridge circuit, for instance).
Are you suggesting that the 'original' circuit consisted of just a loop of wire, joining each of the switch contacts together? What sort of a circuit would that be and what possible use could it be?
I was naturally assuming that the contacts were part of an existing circuit and that they happened to have zero volts across them with no current flowing through them (quite a possibility, in fact it could be part of a balanced bridge circuit, for instance).
Ratch said:sophiecentaur,
Nope, I make no assumptions about whether the switch is connected to a circuit or stands alone. All I am saying is that you cannot definitively determine whether the switch is open or closed by just examining the voltage across it or the current through it. A physical examination of the contacts is required to definitively determine whether the switch is open or closed.
Ratch
So all those 'black box' exercises we did at School and all the measurements done, daily, on components are a waste of time?
We have to see what it actually looks like before we can tell the impedance of a circuit element.
I'm not sure of your point here.
There are many examples of systems into which we cannot look. Opening them up could even destroy them or alter their state.
A philosophy of measurement surely can't be based on what we infer from the outward appearance of a component.
The point was made in a very early post that 0/0 is indeterminate and that's really an end to it.
You need to have at least a finite value for one or the other in order to infer anything about the resistance of a component.
'Visual' observation is just not reliable.
Surely it is obvious that you need to know both current and PD in order to measure the resistance. Resistance is actually defined in terms of the two variables taken together
Your visual inspection issue is a total red herring. It is not part of the Set of 'electrical measurements'.
Visual inspection of contacts is not sufficient at all. They could be made of a shiny insulator,
(And, in any case, the OP did not introduce the state of a switch into the argument).
You would need extra chemical analysis, at least.
On the other hand, an electrical measurement of V and I would tell you how your test subject will behave 'electrically', which is what we want to know (because we are seeking to find the resistance).
@ratchswayam007 said:When Voltage across two points is 0 & current flowing through that connection is 0. Is it a short circuit or open circuit?
Does that (original) post in any way imply a 'mechanical switch'?
Why are you obsessed with your special case of a metallic switch with 'visible' contacts?
What has that got to do with the OP?
When will you ever find even the mechanical switch in your argument where there is a pure short circuit?
Resistance may be relevant for any switch you care to choose so what has the position of a lever got to do with the question.
We have agreed that you need to know V and I to be certain of the electrical characteristic so I still don't know what extra point you are trying to make that has any bearing on the OP.
We can either discuss the Maths of 0/0 or discuss the business of electrical measurement without any power supply but they both end up with the same conclusion. That conclusion is not allowed to contain the concept of visual inspection because that is just one special case.
So a piece of wire is a switch? (That's a short circuit)
The OP is about two points in a circuit. You are merely implying that he means a switch (and, if you read later, he is definitely not talking about a switch.)
Switches don't always do what you expect from their appearance but the will always have some value of resistance. The proof of the pudding is in the eating. If I find that a sealed switch happens to have a low resistance then for my purposes, the state of the switch is closed and the circuit that it is put into is likely to agree with me.
Why are you so much in love with switches? They are only extremes of a variable resistance. You can't determine anything about either without applying some I or some V.
It helps to stick to the point when possible rather than to chase wild geese
The OP said nothing about switches and, later, specifies what is happening in a balanced bridge circuit. Switches just elbowed their way into the thread.
A piece of wire is electrically the same as a closed switch - does that make it a switch? Two points in a circuit have zero resistance between them. Does that imply there must be a closed switch joining them? That was my point.
There are millions of switches (electronic / relays / marine grade etc. etc.) where you cannot observe their contacts. Observability is not a universal attribute of switches. BUT their resistance definitely is. The state of a switch (measured electrically) IS its state because that is how it is behaving in a circuit. Seeing is NOT necessarily believing. If you have ever done serious fault finding, you will know that.
After a while on PF , you will find that people who post questions on the forum really appreciate answers and discussion points that converge on what they want to know. Some of the questions are posted by absolute beginners who cannot distinguish between wheat and chaff. Continually dragging this thread in the direction of switches when the poor OP wanted to know about bridge circuits is not fair to him.
"We" are talking about switches only because you won't let them drop and address the main subject of the thread, which is about two unspecified points in a circuit.
Why not start a separate thread entitled something like "Is a switch really 'on' when I measure zero ohms across its contacts"? Then see what people have to say.
Does every open circuit, you come across, consist of an open switch and does every branch, with zero resistance, consist of a closed switch?
The OP asked a general question because it applies in many cases and he was, presumably, trying to get a general answer. Switches are definitely not the most general of components that one could consider. They are not even the only components with binary states.
If a switch is faulty, is its 'state' what is marked on the front or is it the resistance that it presents to a circuit?
Which 'state' will the circuit respond to, the actual one or the nominal one?
Which state actually counts?
I suggest that you should read a few more threads, posted by beginners and you may get to realize that people don't always know what actual question they should be asking. A sensitive answer will try to find this out.
Ratch said:If they don't understand or disagree, they can engage me further.
Ratch
When V=0 and I=0, it means that there is no voltage or current flowing through a circuit. This can occur in two scenarios - an open circuit or a short circuit.
An open circuit is a circuit where there is a break or gap in the path of the current. This prevents the flow of electricity and results in V=0, I=0. It can be caused by a disconnected wire, a blown fuse, or a faulty component.
A short circuit is a circuit where the current follows an unintended path with little to no resistance. This can occur when two wires touch each other, or when there is a damaged component. It results in a sudden increase in current flow and can be dangerous if not addressed.
To determine if there is an open circuit, you can use a multimeter to measure the resistance between two points in the circuit. If the resistance is infinite, it indicates an open circuit. To determine if there is a short circuit, you can measure the resistance between two points and if it is very low or zero, it indicates a short circuit.
To fix an open circuit, you will need to identify and repair the break in the circuit. This could involve reconnecting a wire, replacing a blown fuse, or fixing a faulty component. To fix a short circuit, you will need to identify and remove the unintended path of current. This could involve separating two touching wires or replacing a damaged component.