Helpful notes: The speed v=√(GM/(R+h)) which is required for an artificial satellite to be set at orbit, is one that its Δx is drawn on the reference frame (call it FR2) that does not move together with the self-rotating movement of the earth. Because whereas it has the speed v=√(GM/(R+h)), the Δx of its speed which is drawn on the reference frame (call it FR1) that moves together with the self-rotating movement of the earth, is zero. The geostationary orbit can only happen at the height of ~35,000km above the ground (see http://imagine.gsfc.nasa.gov/docs/ask_astro/answers/970408d.html). My question is: Is it possible to set an artificial satellite at an orbit at the geostαtionary height (35,000), and the direction of its motion (its motion Δx that is drawn on the FR2) to be the opposite of the geostationary satellites? (It IS possible as it seems at the moving drawing at http://en.wikipedia.org/wiki/Satellite). If-since it is possible, then the speed that it must have is again v=√(GM/(R+h))?