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V (t ) = 5sin (t ) [V]

  • Thread starter XodoX
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  • #1
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1. A circuit element is shown below, with the voltage v(t) and the current i(t) defined. The
voltage and current are given as
v (t ) = 5sin (t ) [V]
i (t ) = −10cos (t ) [A] .
Calculate the power that the element is delivering.

b) For the same circuit in the previous problem, calculate the amount of energy that the circuit
element absorbs between t = 0 and t = 1 .


I don't get the b0 part. The solution for the first part is 50 sin(t) cos(t) [W]. How do I get the amount of energy for that time frame?
 

Answers and Replies

  • #2
berkeman
Mentor
56,656
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1. A circuit element is shown below, with the voltage v(t) and the current i(t) defined. The
voltage and current are given as
v (t ) = 5sin (t ) [V]
i (t ) = −10cos (t ) [A] .
Calculate the power that the element is delivering.

b) For the same circuit in the previous problem, calculate the amount of energy that the circuit
element absorbs between t = 0 and t = 1 .


I don't get the b0 part. The solution for the first part is 50 sin(t) cos(t) [W]. How do I get the amount of energy for that time frame?


What kind of a circuit element is it? Why are they asking about delivering power in one part, and absorbing power in the other part?

To get energy over a time period, you just integrate the power multiplied by dt over the time interval.
 
  • #3
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I forgot how to take the integral of cos/sin :confused:

u= sin(t) du=cos(t) dt

Maybe you can explain the next step to me:) I think that once I got the result of it I am done.
 
  • #4
berkeman
Mentor
56,656
6,559


I forgot how to take the integral of cos/sin :confused:

u= sin(t) du=cos(t) dt

Maybe you can explain the next step to me:) I think that once I got the result of it I am done.
The wikipedia.org article on integration by parts is pretty reasonable:

http://en.wikipedia.org/wiki/Integration_by_parts

.
 

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