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by calculating the fourier series for |sin x| it was found that,

[tex] \sum_{n=1}^\infty \frac 1{(2n-1)(2n+1)}=1/2[/tex].

How can i find the value of -

[tex] \sum_{n=1}^\infty \frac 1{(2n-1)^2(2n+1)^2}[/tex] ?

Thanks

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# Homework Help: Value of a inf. series

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