- #1
clw
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Homework Statement
I am confused with the idea that the value of a delta function is infinity but when given a graph why is there an amplitude/magnitude value for the delta function. I have attached a graph. Assuming the phase is zero I'm trying to write a fourier transform for it.
Homework Equations
G(f) = |G(f)| [itex]e^{j\vartheta}[/itex]
The Attempt at a Solution
I know that it is a shifted impulse function so would it just be 3δ(f-5)+3δ(f+5)? Any help would be very much appreciated I'm just having a hard time grasping the idea of impulse function having an infinite value but there's an amplitude of 3?