Van de Graff Current: Solving Homework Equation

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In summary, the problem involves a Van de Graaff electrostatic generator with a rubberized belt that travels at a velocity of 20 meters/sec and has a surface charge density high enough to create a field of 40 statvolts/cm on each side. The task is to find the necessary surface charge to produce this field and the current in milliamps. The charge is carried on the surface of the belt and the setup resembles a capacitor with an electric field between the two sides.
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Homework Statement


In a Van de Graaff electrostatic generator, a rubberized belt 30 cm wide travels at a velocity of 20 meters/sec. The belt is given a surface charge at the lower roller, the surface charge density being high enough to cause a field of 40 statvolts/cm on each side of the belt. What is the current in milliamps?


Homework Equations


I = nqua
E= 4(pi)kq?


The Attempt at a Solution


There might be some sort of Gaussian surface to be used here, I have the avg velocity (u), the area (a), the charge (q), just need the electrons per cubic centimeter to create such a field.
 
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  • #2
the surface charge density being high enough to cause a field of 40 statvolts/cm on each side of the belt
what is the surface charge [itex]\sigma[/itex] necessary to produce an electric field of 40 statvolts/cm on each side of the belt? The charge is carried on the surface of the belt, not throughout.
 
  • #3
Electric charge is generated on the inside of belt at the bottom by contact with the roller (made of a different material) as it is driven over it. The field of this charge on the inside of the belt causes the brushes (sharp points with charge induced on them due to the presence of the field) next to the roller at the bottom to ionize the air (tips are charged oppositely to that of roller). Ions/charge out of the air around the brushes are then attracted towards the roller and sits on the outside of the belt. These are of opposite charge than that of the roller. It is these charges that are "removed" at the top of the belt with a similar mechanism (ionizing the air near the brushes at the top and being canceled out). While the air is ionized at the top charges are fed into the brushes from the air, continually being conducted away to the sphere.

The belt therefore carries charges of opposite charge on its outsides surfaces and the situation looks very much like a capacitor with an electric field from the one to the other side.

http://amasci.com/emotor/belt.html
 
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1. What is Van de Graff current?

Van de Graff current is a type of electrical current that is produced by a Van de Graff generator. It is a continuous flow of charged particles, such as electrons or ions, along a conductor.

2. How is Van de Graff current related to the homework equation?

The homework equation, also known as the Kirchhoff's current law, states that the total current flowing into a junction must equal the total current flowing out of the junction. Van de Graff current follows this equation as it is also a type of electrical current.

3. How is Van de Graff current measured?

Van de Graff current can be measured using an ammeter, which is an instrument that measures the flow of electrical current. The ammeter is placed in series with the conductor that the Van de Graff current is flowing through.

4. What factors affect the magnitude of Van de Graff current?

The magnitude of Van de Graff current is affected by the voltage of the Van de Graff generator, the resistance of the conductor, and the distance between the Van de Graff generator and the conductor.

5. How is Van de Graff current used in practical applications?

Van de Graff current has various practical applications, such as particle accelerators, electrostatic precipitators, and electrostatic coating. It is also used in scientific experiments and demonstrations to produce high-voltage electrical discharges.

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