Van der Waal's: Exploring Fluctuating Dipoles in Molecules

In summary: So in summary, Van der Waal's theory explains that the fluctuating dipole of one molecule can induce dipoles in other neutral molecules or atoms due to the coupling between the electrons and the fluctuating electromagnetic fields of the quantum vacuum. These induced dipoles are position dependent and thus cause a force between molecules. The dipole moment can be represented as qα where α is the polarizability of the molecule.
  • #1
hasan_researc
170
0
My lecturer writes the following in his lecture notes:
“Van der Waal’s : Fluctuating dipole of molecules induces dipoles in molecules or other-
wise neutral atoms (eg noble gases)”

Does a fluctuating dipole refer to a dipole that is changing its orientation in space?

How causes a dipole to be formed within a molecule, provided that there are no nearby fluctuating dipoles?

Finally, how can the fluctuating dipole of one molecule induces dipoles in molecules or other-
wise neutral atoms?

Tahns in advance for any help!
 
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  • #2
The dipole can be thought of as being something akin to
[tex] \mathbf{p} = \alpha (t) \hat{z} [/tex]
where
[tex] -d \leq \alpha (t) \leq d[/tex]

In other words, the fluctuating dipole is like a harmonic oscillator where the positive nucleus lies at the equilibrium position and the electron is moving back and forth in space. In the above I just restricted it along a single dimension for simplicity though. So yes, the dipole is changing its orientation and its strength.

The original paper by London did not make any assumptions on how these dipoles are fluctuating. In quantum mechanics, the harmonic oscillator has a non-zero energy ground state and is always oscillating. London assumed that the electrons in the polarizable atoms or molecules behave like the quantum oscillator. Thus, the basic assumption assumes that the dipoles will always fluctuate but he did not give a more basic reason.

One reason for this can be found by the fact that the quantum vacuum contains fluctuating electromagnetic fields even in the ground state. If we use quantum field theory to describe the electromagnetic fields, we find that in the ground state, called the vacuum where there are no photons, the expectation (mean) value of the electric and magnetic fields is zero. However, the fields do fluctuate about the zero point because they are also described as harmonic oscillators. The fluctuating electric and magnetic fields couple with the electrons in an atom or molecule. This coupling causes the fluctuations that give rise to the dipole moment that London assumed in his paper.

So in short, one way to think about it is that the electrons couple with the vacuum fields which cause them to fluctuate from their normal orbitals and this gives rise to a fluctuating dipole moment.

Now this new fluctuating dipole moment gives rise to its own electric field. This electric field will act on a nearby atom or molecule and induce a charge separation between the nucleus and orbiting electron and thus cause another dipole moment (this is the same mechanism as how the vacuum fields create the original fluctuating dipole moment).

The difference with the fluctuating dipole moment that is induced by the neighboring atom versus the vacuum induced moment is that the vacuum induced moment is independent (more or less) of the position of the atom in space. However, the position of the two atoms relative to each other affects the dipole moment that one atom's dipole induces in the other atom. The fact that the induced dipole moment is dependent upon position means that the energy of the system is position dependent and thus there is a force (since force is the gradient of the potential of the system).
 
  • #3
Thanks! Your discussion is very clear.

I am wondering if the diople moment should equal q times alpha.
 
  • #4
hasan_researc said:
Thanks! Your discussion is very clear.

I am wondering if the diople moment should equal q times alpha.

Eh, depends. The dipole moment is always time-varying. However, a lot of times we work in the frequency domain which assumes a exp(-i \omega t) time dependence. So often when you are given a dipole moment described as \alpha q, they really mean \alpha q exp(-i \omega t). So we can certainly think of the dipole moment as some q\alpha but there still needs to be an inherent time dependence somewhere since the charges are being acted upon by a time-varying force. As for \alpha versus \alpha q, it doesn't matter. I'm just using \alpha as a constant here in which we can absorb the charge. We generally talk about the molecules or atoms have a polarizability of \alpha as opposed to being a direct dipole of q d where d is the distance of separation between two charges of strength q.
 
  • #5


I can provide a response to the content on Van der Waal's and fluctuating dipoles in molecules.

Firstly, yes, a fluctuating dipole refers to a dipole that is constantly changing its orientation in space. This is due to the constant movement and vibration of molecules, which can cause the distribution of electrons to be uneven at any given moment, resulting in a temporary dipole.

To understand how a dipole is formed within a molecule, we need to look at the nature of chemical bonds. In a covalent bond, two atoms share a pair of electrons, but these electrons are not always shared equally. This unequal sharing of electrons can result in a separation of charge, creating a dipole moment within the molecule. This can also happen in polar covalent bonds, where the electrons are not equally shared between the atoms.

Now, how can the fluctuating dipole of one molecule induce dipoles in other molecules or otherwise neutral atoms? This is known as the induction effect, where the fluctuating dipole of one molecule can influence the distribution of electrons in nearby molecules or atoms. This is due to the temporary dipole creating an electric field that can attract or repel electrons in other molecules or atoms, resulting in a temporary dipole in those nearby particles.

Overall, Van der Waal's forces play a crucial role in the interactions between molecules and atoms, and the concept of fluctuating dipoles helps us understand how these interactions occur. I hope this helps clarify the concepts for you.
 

1. What is Van der Waal's force?

Van der Waal's force is a type of intermolecular force that arises from the interactions between fluctuating dipoles in atoms or molecules. It is a weak force that is responsible for the attraction between non-polar molecules, such as noble gases and hydrocarbons.

2. How does Van der Waal's force affect the properties of molecules?

Van der Waal's force can impact various properties of molecules, including melting and boiling points, viscosity, and surface tension. It can also play a role in the stability and organization of molecular structures.

3. What is the significance of Van der Waal's force in biology?

Van der Waal's force is crucial in biological systems as it helps hold together large biomolecules, such as proteins and DNA. It also plays a role in the interactions between molecules in cell membranes and the binding of ligands to receptors.

4. How does temperature affect Van der Waal's force?

The strength of Van der Waal's force is directly proportional to temperature. As temperature increases, the kinetic energy of molecules also increases, causing greater fluctuations in dipoles and, therefore, a stronger Van der Waal's force.

5. Can Van der Waal's force be observed in everyday life?

Yes, Van der Waal's force can be observed in various everyday occurrences, such as the condensation of water droplets on a cold surface, the adhesion of gecko feet to surfaces, and the ability of some insects to walk on water. It also plays a role in the cohesion of liquids and the formation of gas bubbles in carbonated drinks.

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