Vapor Pressure and Raoult's Law

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Qube
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Homework Statement



The vapor pressure of pure water at 45 degrees C is 71.9 mm Hg. What is the vapor pressure when 18g of sucrose (MM = 342.3g/mol) is added to 82g of water?

Homework Equations



VP of solution = mole fraction of solvent * VP of pure solvent

The Attempt at a Solution



82g of water / (18g/mol) = 4.555... moles of water.

18g of sucrose / (342.3g/mol) = 0.0525 moles of water

Mole fraction of solvent (water) = 0.988.

0.988 * 71.9 mm Hg = new vapor pressure of 71.1 mm Hg.

Is my work correct? It's 3 AM here and I'm just a bit concerned about how accurate I am in doing these practice problems.
 

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