Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Vapor pressure in equilibrium

  1. Mar 8, 2005 #1
    Hi
    I have difficulties with a problem that my teacher gave in assignement. Teh teacher said it was a bit higher than our level but I think it far above what I am able to do! so here it is :

    The vapor pressure in equilibrium with pentane-hexane solution at 25°C has a mole fraction of pentane equal to 0.15 at that temperature. What is the mole fraction in the solution?

    Up to now I found that the vapor pressure of pentane is 511 torr and the one of hexane is 150 torr. I think that I should use Raoult's law but my attempts were not concluant... I hope someone will be able to answer my question.
     
  2. jcsd
  3. Mar 12, 2005 #2

    Gokul43201

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    [tex]P^o (P) = 511~,~~P^o (H) = 150 [/tex]

    [tex]P(P) = \chi (P.solution) * P^o (P)= 0.15P(tot) [/tex]

    [tex]=>~0.15P(tot) = \chi (P)* 511 [/tex]

    [tex]And~0.85P(tot) = (1 - \chi(P))*150 [/tex]
     
    Last edited: Mar 12, 2005
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Vapor pressure in equilibrium
  1. Vapor Pressure (Replies: 3)

  2. Vapor pressure (Replies: 1)

  3. Vapor pressure (Replies: 1)

  4. Vapor pressure (Replies: 6)

Loading...