The vapor pressure of water at 25.0 C is 23.8 torr, and the heat of vaporization is 43.9 kJ/mol. What is the vapor pressure (atm) of water at 59.8C?
The Attempt at a Solution
P1=23.8 torr = .031315789 atm
ΔH=43.9 KJ/mol=43900 J/mol
R= 8.31 (J)/(mol∙K)
plugged into the equation and keep getting the wrong answer.
Can someone please help.
ln(p2) - ln(.031315789) = -(439005)/(8.31) * [(1/332.8) - (1/298)]
HELP idk what i did wrong