In online examples of variable displacement systems with swash-plate pumps, the input pump & motor are usually of equal size. When the constant RPM input pump is at full tilt (max displacement) the fixed displacement motor is at the same RPM for a 1:1 ratio, and when the pump is at no tilt (no displacement) the motor doesn't turn at all, 1:0 ratio. So, the output can reach the same speed or lower. If a design requirement was that ratio is 1:3 at maximum displacement, would designing the input pump's pistons to be larger, moving 3 times the volume of the motor's pistons do the trick? I'm trying to design a hydrostatic system for a vehicle, but haven't seen any examples of where the output is speed can be faster than the input. Thanks in advance.