- #1

doubled

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I have attached the problem of interest.

I think I am having trouble calculating the standard deviation for part a.

D=A-B-C

E(A)=10 E(B)=2 E(C)=2 sigma(A)=0.1 sigma(B)=0.05 sigma(C)=0.1

where sigma=standard deviation

so to find SD....:

V(D)=V(A-B-C)=sigma(A)2+sigma(B)2+sigma(C)2=(0.1^2)+(0.05^2)+(0.1^2)=0.0225

sigma(D)=(V(D))^0.5=0.0225^0.5=0.15

The book's answer is 0.1225. I do not see any glaring mistakes. Could someone please take a look?

The book may be wrong. I just want to make sure that it is not me that's wrong.

I think I am having trouble calculating the standard deviation for part a.

D=A-B-C

E(A)=10 E(B)=2 E(C)=2 sigma(A)=0.1 sigma(B)=0.05 sigma(C)=0.1

where sigma=standard deviation

so to find SD....:

V(D)=V(A-B-C)=sigma(A)2+sigma(B)2+sigma(C)2=(0.1^2)+(0.05^2)+(0.1^2)=0.0225

sigma(D)=(V(D))^0.5=0.0225^0.5=0.15

The book's answer is 0.1225. I do not see any glaring mistakes. Could someone please take a look?

The book may be wrong. I just want to make sure that it is not me that's wrong.