Variation of parameters

  • #1
lonewolf219
186
2
I just realized you can use variation of parameters (VOP) to solve for homogeneous 2nd order equations. I see it takes much longer to do so. But I was wondering why, if you use VOP, the u and v functions are 0. Is this because the coefficients of the homogeneous equation are constant, or possibly because the differential equation is equal to 0 to begin with?
 

Answers and Replies

  • #2
obafgkmrns
121
0
One way to look at it is simply to note that VOP results in a valid solution to the problem. The uniqueness theorem assures you that you have the only correct solution.
 

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