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Various properties of waves

  1. Apr 13, 2014 #1
    I have a few waves questions I would really like to have addressed. I'll post my logic/solution for each question and any feedback is welcome.

    Q. 10: This one seems pretty straight forward but shouldn't the units be 3.0 rad/m? Since x is in meters and we're not changing the order of magnitude for any other variables, I don't quite see how the units cancel out properly...I'd just like to confirm this.

    Q. 20 and 21: This seems also pretty simply but I may be missing something here. To find instantaneous velocity is to take the derivative (find slope of tangent) at a point. Looking at the question like this, my answer for 20 would be E and 21 would be D. Am I missing something fundamental here?

    Q. 31: This question also didn't make complete sense to me. Looking at 3, the tension appears to be the greatest since there's one string and 2 masses for which it must be keep up. 2 looks like the lowest and 1 is intermediate, since FT ~ v2. Once again, am I missing something big here?

    Any help with these questions would be great! Thanks!
     

    Attached Files:

  2. jcsd
  3. Apr 13, 2014 #2
    For Q10, you're right, the units should be rad/m.

    For Q20 and Q21, try to imagine what happens to point P as the wave moves to the right. The waves are traverse in both cases, so a point "on" the wave cannot by definition have a longitudinal velocity component, just a traverse component, hence it can only go up or down.

    As for Q31, I don't see any sort of picture so I can't really help out much.
     
  4. Apr 14, 2014 #3
    q. 31
     

    Attached Files:

  5. Apr 15, 2014 #4
    If you haven't done so already, draw free body diagrams for all the cases depicted. You can then figure out the tensions in all of them. Notice that case 1 and 3 are equivalent because the forces on both ends of the rope are the same (in the first case, the wall must exert a force equal in magnitude to that of the weight of the block, otherwise it wouldn't be in equilibrium anymore).
     
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