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Varying the Minkowski Metric

  1. Jun 25, 2015 #1
    So I was wondering, is the variation of the Minkowski Metric zero? As in ##{\delta}{\eta}_{\mu\nu}=0## . I would think this is the case because the components of the Minkowski Metric are just numbers (either +1 or -1), so varying it gives you 0. Is this correct?
     
  2. jcsd
  3. Jun 25, 2015 #2
    What do you mean ? ημν is just and bunch of zero and +/- 1 every where, so normally it's differential is equal to zero !
     
  4. Jun 25, 2015 #3
    Right, well that's what I was asking haha. I just needed some reassurance that it was the correct answer, thank you.
     
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