A land surveyor walks 5200m @ 330 degrees and then turns and goes an additional 3000m @ 180 degrees. Find his final displacement using the law of sines/cosines.
I know the law of sines is a/sinA = b/sinB = c/sinC, and the law of cosines is a^2=b^2 + c^2 - 2bc cos A. I just don't know how to get started.
The Attempt at a Solution
I have no attempt at this solution except for a picture.