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EDIT: ****Nevermind, I just mis-typed everything into my calculator. I had to put my X and Y values in parenthesis - ie sqrt((29.47)^2 + (-5.32)^2)**************

I *think* I am doing this right, but I can never get the right answer. Does anybody notice what is going wrong?

The correct answer to this problem is an angle of 10.2 degrees and a magnitude of 30.2 m.

A football player runs the pattern given in the drawing by the three displacement vectors A, B, and C. The magnitudes of these vectors are A = 5.00 m, B = 15 m, and C = 18 m. Using the component method, find the magnitude and direction (theta) of the resultant vector A + B + C.

http://univirtual.info/elementaryphysics/art/images/cutnell3158c01/image_n/ngr021.gif [Broken]

Dx: Ax + Bx + Cx

Dy: Ay + By + Cy

Ax: (5 cos 90) = 0 m

Bx: (15 cos 0) = 15 m

Cx: (18 cos 325) = 14.74 m

Ay: (5 sin 90) = 5 m

By: (15 sin 0) = 0 m

Cy: (18 sin 325) = -10.32 m *i measured all the angles from the x axis*

Dx = 29.74 m

Dy = -5.32 m

D = sqrt(29.74

theta = tan

I *think* I am doing this right, but I can never get the right answer. Does anybody notice what is going wrong?

The correct answer to this problem is an angle of 10.2 degrees and a magnitude of 30.2 m.

## Homework Statement

A football player runs the pattern given in the drawing by the three displacement vectors A, B, and C. The magnitudes of these vectors are A = 5.00 m, B = 15 m, and C = 18 m. Using the component method, find the magnitude and direction (theta) of the resultant vector A + B + C.

http://univirtual.info/elementaryphysics/art/images/cutnell3158c01/image_n/ngr021.gif [Broken]

## Homework Equations

Dx: Ax + Bx + Cx

Dy: Ay + By + Cy

## The Attempt at a Solution

Ax: (5 cos 90) = 0 m

Bx: (15 cos 0) = 15 m

Cx: (18 cos 325) = 14.74 m

Ay: (5 sin 90) = 5 m

By: (15 sin 0) = 0 m

Cy: (18 sin 325) = -10.32 m *i measured all the angles from the x axis*

Dx = 29.74 m

Dy = -5.32 m

D = sqrt(29.74

^{2}+ -5.32^{2}) =**29.26 m**theta = tan

^{-1}(Dy/Dx) = 10.1 degrees
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