1. The problem statement, all variables and given/known data There are two forces on the 3.2 kg box in the overhead view of the figure below but only one is shown. The figure also shows the acceleration of the box. F1 is in Q I and F2 is in Q III a = 12m/s2 there is a picture here that I do not know how to upload -- it shows F1 in the +x direction ( 0º ) and F2 in Q III in the -x and -y direction at 30º from the y axis in the SW direction then below that it gives the a=12m/s2 I am not sure if that means a=12m/s2 for F2 or if that is for the fnet = ma where that is a...... (a) Find the second force in unit-vector notation. (b) Find the second force as a magnitude and direction. 2. Relevant equations and 3. The attempt at a solution (a) Find the second force in unit-vector notation. Fnet = ma so Fnet = 3.2kg * 12m/s2 = 38.4N F2 = 38.4N - F1 = 38N - 20N = 18.4 (b) Find the second force as a magnitude and direction. F2=ma - F1 = [3.2kg * 12m/s2]-20N = 18.4N F2x = 18 cos 240º = -9i F2y = 18 sin 240º = -15.59i I am supposed to be getting -39.2iand -33.3j for F2 for part A and 51.4N (-140)º for part b. if they gave me ø how am I supposed to get -140º for ø? I am very confused with this question.