# Vector and magnitude

1.I only need to know how to get magnitude out of a vector

2. Suchs as 25m = a cos (60 degrees)

3. I tried 25m/cos/60degrees but it don't seem right

please assist I know it isn't a real problem it's just the step that I need help. If you could write it in fomula form AX=A cos (theta) solving for "A". And if you can show me how to solve for "theta" as well please.

magnitude is simply the length of the vector. if you are using cos then it sounds like what you really need is the x or y component.

I see that I may have been unclear Ax is the x component. I have Ax and I hav ethe angle theta what I do no thave is the magnitude.

Ax is written A(sub)x(/sub) except that you use brackets.

what do you mean solve for A??? thats trivial. A*cos(theta) is no different from A*B.

theta is a little harder. give me a minute.

Thanksyou
I have Ax = A cos $$\Theta$$
where I know Ax and $$\Theta$$
how do I find A