Vector and magnitude

  • #1
1.I only need to know how to get magnitude out of a vector



2. Suchs as 25m = a cos (60 degrees)


3. I tried 25m/cos/60degrees but it don't seem right

please assist I know it isn't a real problem it's just the step that I need help. If you could write it in fomula form AX=A cos (theta) solving for "A". And if you can show me how to solve for "theta" as well please.
 

Answers and Replies

  • #2
2,268
7
magnitude is simply the length of the vector. if you are using cos then it sounds like what you really need is the x or y component.
 
  • #3
I see that I may have been unclear Ax is the x component. I have Ax and I hav ethe angle theta what I do no thave is the magnitude.
 
  • #4
2,268
7
Ax is written A(sub)x(/sub) except that you use brackets.
 
  • #5
2,268
7
what do you mean solve for A??? thats trivial. A*cos(theta) is no different from A*B.

theta is a little harder. give me a minute.
 
  • #6
Thanksyou
I have Ax = A cos [tex]\Theta[/tex]
where I know Ax and [tex]\Theta[/tex]
how do I find A
 

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