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Vector calcululus

  1. Sep 16, 2014 #1
    1. The problem statement, all variables and given/known data
    can someone help prove this

    (∇ x A) x A =(A.∇)A-1/2∇Modulus(A power2)

    2. Relevant equations



    3. The attempt at a solution
    (∇ x A) x A =(A.∇)A-∇(A power2)
     
  2. jcsd
  3. Sep 16, 2014 #2

    SteamKing

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    Calcululus - lu = Calculus

    Have you tried expanding out both sides according to the definition of the Del operator and the cross product?

    It looks like a moderately long slog thru vector algebra after that point.
     
  4. Sep 17, 2014 #3
    Hi
    Yes I did but what I achieve is the last term without factor of (1/2), don't know what to do now, what I got is (vector A power 2) and required is 1/2*(Modulus( A square)), is there any difference (A square) and Modulus(A square)
     
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