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Vector Calculus Problem

  1. Sep 18, 2008 #1
    Equation for plane that passes through the point (2,-1,3) and is perpendicular to the linev=(1,-2,2)+t(3,-2,4)?

    I'm not exactly sure where I'm supposed to go since the only examples in my book show the plane perpendicular to a vector written in a different form. Not in this one
  2. jcsd
  3. Sep 18, 2008 #2


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    If a line is given in the form (x0, y0, z0[/sub])+ t(A, B, C) then Ai+ Bj+ Ck is a vector pointing in the direction of the line. Is that enough?
  4. Sep 18, 2008 #3
    So is it supposed to be that I can find the plane based on simply that vector since any of the normal vectors would be orthogonal to the plane?
  5. Sep 18, 2008 #4


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    Well the normal will be perpendicular to the plane, but so is the line v. So wouldn't the normal to the plane be given by the direction of the line v? Given the normal to the plane and a point in the plane, you should be able to calculate the equation of the plane.
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