1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Vector calculus problem

  1. Jan 25, 2005 #1
    f = 2xy in the x dir, (x^2 - z^2) in the y dir, -3xz^2 in the z dir.
    particle travles from (0,0,0) to (2,1,3) along the segments (0,0,0) ->(0,1,0)->(2,1,0)->(2,1,3)

    the integral is F dot product with dl.
    i cant figure this out.

    do i dot product each part individually and evaluate? i mean dot the x component of F and dl and evaluate them on an integral?
     
  2. jcsd
  3. Jan 25, 2005 #2

    Galileo

    User Avatar
    Science Advisor
    Homework Helper

    You have to cut your integral into 3 parts for the three line segments:

    [tex]\int_{(0,0,0)}^{(0,1,0)}\vec F \cdot d\vec l+\int_{(0,1,0)}^{(2,1,0)}\vec F \cdot d\vec l+\int_{(2,1,0)}^{(2,1,3)}\vec F \cdot d\vec l[/tex]

    Since each of the the line segments are parallel to either the x,y or x-axis, getting [itex]d\vec l[/itex] is very simple.
     
  4. Jan 25, 2005 #3

    so the first integral would be from (0,0,0) to (0,1,0), and i would be evaluating 2xy*dx? thats the dot product of Fx and dl sub x. what do i do with the y?
    i tried it this way earlier and i get a final answer after evaluating the three integrals of -22. the book says -50.
     
  5. Jan 25, 2005 #4

    Galileo

    User Avatar
    Science Advisor
    Homework Helper

    Note the direction. If you go from (0,0,0) to (0,1,0) in a straight line, then you only have the y-component to worry about (not the x!)
    So the first integral is:

    [tex]\int_0^1 F_y(0,y,0)dy=0[/tex]
    since the y component of [itex]\vec f[/itex] is zero along this line.
    Do the same for the 2nd and 3rd integral. The second yields 4, the third is -54.
     
  6. Jan 25, 2005 #5
    ive got another problem, my electro-magnetics prof didnt get a chance to do any examples on this stuff. D = 2 Ro z^2 in the Ro dir, and Ro cos^2 theta in the z dir.
    find closed surface integral of D dot Ds.
    0<Ro<5
    -1<z<1
    0<theta<2pi

    is this the same thing or is it different?
     
  7. Jan 25, 2005 #6
    this is the same problem but this time they want me to evaulate it on the straight line from (0,0,0) to (2,1,3).
    everything i can find on the net wants me to parametrize it, and the book doesnt say anything about that. so im sure theres an easier way to do it.

    the book gives the answer of -39.5
     
  8. Jan 25, 2005 #7
    if i make z = 3/2 x and y = 1/2 x and substitute those into the integral of F dot dl i end up with an answer of -27.66667. the way im doing it makes sense from the things ive seen on the net. but the book gives an answer of -39.5. ??
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Vector calculus problem
  1. Vector Calculus (Replies: 3)

  2. Vector calculus (Replies: 4)

  3. Vector calculus (Replies: 2)

  4. Vector Calculus (Replies: 4)

Loading...