Reading the Feynman Lectures,(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\nabla \times (\nabla T)=(\nabla \times \nabla) T[/tex], is achieved by analogy to the analogous case for [itex]\mathbf{A} \times (\mathbf{A} T)=(\mathbf{A} \times \mathbf{A}) T[/itex],where T is a scalar field in all cases.

While this is obvious if [itex] \nabla [/itex] were to be replaced by a vector, I'm a complete novice when it comes to operators- is it a general rule in vector calculus that operators behave pretty much like vectors (apart from needing 'feeding', of course)?

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# Vector calculus quick question

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