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Vector calculus

  1. Apr 15, 2009 #1
    is it true that if [itex]\nabla \cdot \vec{F}=0 , \nabla \times \vec{F}=0[/itex] then [itex]\vec{F}=0[/itex]???
     
  2. jcsd
  3. Apr 15, 2009 #2

    robphy

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    Suppose [tex]\vec F=3\hat x \ldots[/tex]
     
  4. Apr 16, 2009 #3
    the divergence of 3x is 3 not 0 though?
     
  5. Apr 16, 2009 #4

    robphy

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    By [tex]\hat x[/tex], I mean what you might have seen as [tex]\hat \imath[/tex]....
    that is,
    [tex]\vec F= (3) \hat \imath [/tex]
    or
    [tex]\vec F= (3,0,0) [/tex]
    ...that is, a nonzero constant vector field.
     
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